Page Comparison

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Ft	750000 kN/m2
Ab	Mathinline body --uriencoded--$$ \normalsize A_b = \dfrac%7B \pi d%5e2%7D %7B4%7D = \dfrac%7B \pi 24%5e2%7D %7B4%7D = 452.389 $$	AISC DG-4-2nd 3.7
Pt	Mathinline body --uriencoded--$$ \normalsize P_t = F_%7Bt%7DA_b = 750 \times 10%5e%7B-3%7D \times 452.389 = 339.292 $$
h0	473.038 mm
h1	315.271 mm
dm	394.154 mm
Mreq	119.655 kNm
Nreq	-27.504 kN
Rreq	Mathinline body --uriencoded--$$ \normalsize R_%7Breq%7D = \dfrac%7B M_%7Breq%7D %7D%7Bd_m%7D + \dfrac%7B N_%7Breq%7D %7D%7B2%7D = \dfrac%7B 119.655 %7D%7B394.154%7D + \dfrac%7B -27.504 %7D%7B2%7D = 289.822 $$
Rn	Mathinline body --uriencoded--$$ \normalsize R_n = \dfrac%7B 2 P_t ( h_o + h_1 ) %7D%7B d_m %7D $$ Mathinline body --uriencoded--$$ \normalsize R_n == \dfrac%7B 2 \times 339.292 \times (473.038 + 315.271 ) %7D%7B 394.154 %7D =1357.17 $$
ΦRn Image Removed	Mathinline body $$ \normalsize \varphi R_n = 0.75 \times 1357.17 = 1017.876 $$

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The required end plate thickness, t_p, for four bolts stiffened end plate connection is checked according to AISC 358-16 §6.8

Ab Image Removed	Mathinline body --uriencoded--$$ \normalsize A_b = \dfrac%7B \pi d%5e2%7D %7B4%7D = \dfrac%7B \pi 24%5e2%7D %7B4%7D = 452.389 $$
Pt Image Removed	Mathinline body --uriencoded--$$ \normalsize P_t = F_%7Bt%7DA_b = 750 \times 10%5e%7B-3%7D \times 452.389 = 339.292 $$
Mn Image Removed	Mathinline body $$ \normalsize M_n = 2 P_t ( h_o + h_1 ) = 2 \times 339.292 ( 473.038 + 315.271 ) = 534.934 $$	AISC 358-16 (6.8-5)
Fyp	235000 kN/m2
Yp	2517.347 mm
tp Image Removed	Mathinline body --uriencoded--$$ \normalsize t_%7Breq%7D = \sqrt%7B \dfrac%7B 1.11 \varphi M_n %7D %7B \varphi F_%7Byp%7D Y_p %7D %7D =\sqrt%7B \dfrac%7B 1.11 \times 0.75 \times 534.934 %7D %7B 0.9 \times 235 \times 2517.347 %7D %7D =28.921 $$

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The shear strength of connecting elements in shear is the minimum value obtained according to the limit states of shear yielding and shear rupture. Shear yielding is checked according to AISC 360-16.

Fyp	235000 kN/m2
Ag Image Removed	Mathinline body --uriencoded--$$ \normalsize A_%7Bg%7D = L_p \times t_ p = 420 \times 30 =12600 \; \; \mathrm%7Bmm%5e2%7D $$	AISC 360-16 J4-3
dm	394.154 mm
Mreq	119.655 kNm
Nreq	-27.504 kN
Rreq Image Removed	Mathinline body --uriencoded--$$ \normalsize R_%7Breq%7D = \dfrac%7B M_%7Breq%7D %7D%7Bd_m%7D + \dfrac%7B N_%7Breq%7D %7D%7B2%7D = \dfrac%7B 119.655 %7D%7B394.154%7D + \dfrac%7B -27.504 %7D%7B2%7D = 289.822 $$
Rn Image Removed	Mathinline body $$ \normalsize R_n = 0.6 F_y A_g = 0.6 \times 235 \times 12600 = 1776.6 $$
ΦRn Image Removed	Mathinline body $$ \normalsize \varphi R_n = 1 \times 1776.6 = 1776.6 $$

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