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Ψ | 1.0 | ACI 318M-08 D.5.3.6 |
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body | --uriencoded--$$ \normalsize N_p = 8A_%7Bbgr%7D f_c = 8 \times 7401.592 \times 25000 \times 10%5e%7B-6%7D $$ |
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Mathinline |
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body | $$ \normalsize N_p = 1480.318 $$ |
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| ACI 318M-08 (D-15) |
Abgr | 7401.592 mm2 | |
fc | 25000 kN/m2 | |
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body | $$ \normalsize R_n = \psi N_p = 1.0 \times 1480.318 = 1480.318 $$ |
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| ACI 318M-08 (D-14) |
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body | $$ \normalsize \varphi R_n = 0.70 \times 1480.318 = 1036.222 $$ |
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Required | Available | Ratio | Control |
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28.779 kN | 1036.222 kN | 0.028 | √ |
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The calculation is made using the Elastic method, one of the methods selected in the steel analysis settings tab. In this check, the operation is performed on half of the symmetry axis and is calculated to form a force pair with the required force.
Ab | Image Removed | Fn | Image Removed | Rn | Image Removed | Mathinline |
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body | --uriencoded--$$ \normalsize A_b = \dfrac%7B \pi d%5e2%7D %7B4%7D = \dfrac%7B \pi 24%5e2%7D %7B4%7D = 452.389 $$ |
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Fn | Mathinline |
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body | --uriencoded--$$ \normalsize F_n = 0.450 F_%7Bub%7D = 0.450 \times 1000 =450 $$ |
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Rn | Mathinline |
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body | --uriencoded--$$ \normalsize R_n = F_n A_b = 450 \times 452.389 \times 10%5e%7B-3%7D =203.575 $$ |
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| AISC 360-16 J3-1 |
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body | --uriencoded--$$ \normalsize \varphi R_n = 0.75 \times 203.575 = 152.681 \; \mathrm%7BkN%7D $$ |
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Required | Available | Ratio | Control |
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9.885 kN | 152.681 kN | 0.065 | √ |
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The bearing strength limit states of the base plate, which are “shear tear out” and “ovalization of bolt hole” for both end and inner bolts, are checked according to AISC 360-16.
dh | 24+3=27 mm | |
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body | --uriencoded--$$ \normalsize L_%7Bc,edge%7D = L_e - 0.5d_h = 45 - 0.5 \times 27 =31.5 $$ |
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body | --uriencoded--\begin%7Baligned%7D \normalsize R_n = \mathrm%7Bmin%7D \left[\begin%7Bmatrix%7D 1.2L_c \times t \times F_u \\2.4d \times t \times F_u \end%7Bmatrix%7D\right] \end%7Baligned%7D |
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| AISC 360-16 J3-6a |
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body | --uriencoded--\begin%7Baligned%7D \normalsize R_n = \mathrm%7Bmin%7D \left[\begin%7Bmatrix%7D 1.2(31.5)(42)(469.999 \times 10%5e%7B-3%7D) \\2.4(24)(42)(469.999 \times 10%5e%7B-3%7D) \end%7Bmatrix%7D\right] \end%7Baligned%7D =746.17 |
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Rn Image Removed | Mathinline |
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body | --uriencoded--$$ \normalsize R_%7Bn%7D = n_eR_%7Bn,edge%7D =1 \times 746.17 =746.17 $$ |
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ΦRn Image Removed | Mathinline |
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body | $$ \normalsize \varphi R_n = 0.75 \times 746.17 = 559.628 $$ |
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Required | Available | Ratio | Control |
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9.885 kN | 559.629 kN | 0.018 | √ |
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