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Ab

Mathinline
body--uriencoded--$$ \normalsize A_b = \dfrac%7B \pi d%5e2%7D %7B4%7D = \dfrac%7B \pi 16%5e2%7D %7B4%7D = 201.062\; \mathrm%7Bmm%5e2%7D $$

 

Fnv

Mathinline
body--uriencoded--$$ \normalsize F_%7Bnv%7D=0.450F_%7Bub%7D=0.450 \times 800 = 360\; \mathrm%7BN/mm%7D $$

 

Rn

Mathinline
body--uriencoded--$$ \normalsize R_n = F_%7Bn%7D \times A_b = R_%7Bnv%7D = n ( m F_%7Bnv%7D A_b) $$

Mathinline
body--uriencoded--$$ \normalsize R_n = 4 \times (1 \times 360 \times 201.062 \times 10%5e%7B-3%7D )%7D = 289.53 \; \; \mathrm%7BkN%7D $$

AISC 360-16 J3-1

R n / Ω

Mathinline
body--uriencoded--$$ \normalsize R_n/ \Omega = 289.53 / 2 = 144.765 \; \; \mathrm%7BkN%7D $$

 

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dh

16+2=18 mm

 

Rn

Mathinline
body--uriencoded--\begin%7Baligned%7D \normalsize R_n = \mathrm%7Bmin%7D \left[\begin%7Bmatrix%7D 1.2L_c \times t \times F_u \\2.4d \times t \times F_u \end%7Bmatrix%7D\right] \end%7Baligned%7D

AISC 360-16 J3-6a

Lc,spacing

Mathinline
body--uriencoded--$$ \normalsize L_%7Bc,spacing%7D = s - d_h = 60 - 18 =42\; \mathrm%7Bmm%7D $$

 

Rn-spacing

Mathinline
body--uriencoded--\begin%7Baligned%7D\normalsize R_%7Bn%7D=\mathrm%7Bmin%7D\left[\begin%7Bmatrix%7D 1.2 ( 42) ( 7.1 )(362.846 \times 10%5e%7B-3%7D) \\ 2.4 ( 16 ) ( 7.1 )(362.846 \times 10%5e%7B-3%7D) \end%7Bmatrix%7D\right]\end%7Baligned%7D = 98.926 \; \mathrm%7BkN%7D

 

Rn / Ω

Mathinline
body--uriencoded--$$ \normalsize R_n/ \Omega = 395.704 / 2 = 197.852 \; \; \mathrm%7BkN%7D $$

 

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dh

16+2=18 mm

 

Lc,edge

Mathinline
body--uriencoded--$$ \normalsize L_%7Bc,edge%7D = L_e - 0.5d_h = 45 -0.5 \times 18 = 36\; \mathrm%7Bmm%7D $$

 

Rn

Mathinline
body--uriencoded--\begin%7Baligned%7D \normalsize R_n = \mathrm%7Bmin%7D \left[\begin%7Bmatrix%7D 1.2L_c \times t \times F_u \\2.4d \times t \times F_u \end%7Bmatrix%7D\right] \end%7Baligned%7D

AISC 360-16 J3-6a

Rn-edge

Mathinline
body--uriencoded--\begin%7Baligned%7D\normalsize R_%7Bn%7D=\mathrm%7Bmin%7D\left[\begin%7Bmatrix%7D 1.2 ( 36 ) ( 12 )(362.846 \times 10%5e%7B-3%7D) \\ 2.4 ( 16 ) (12 )(362.846 \times 10%5e%7B-3%7D) \end%7Bmatrix%7D\right]\end%7Baligned%7D = 167.199\; \mathrm%7BkN%7D

 

Lc,spacing

Mathinline
body--uriencoded--$$ \normalsize L_%7Bc,spacing%7D = s - d_h = 60 - 18 =42 $$

 

Rn-spacing

Mathinline
body--uriencoded--\begin%7Baligned%7D\normalsize R_%7Bn%7D=\mathrm%7Bmin%7D\left[\begin%7Bmatrix%7D 1.2 ( 42 ) ( 12 )(362.846 \times 10%5e%7B-3%7D) \\ 2.4 ( 16 ) (12 )(362.846 \times 10%5e%7B-3%7D) \end%7Bmatrix%7D\right]\end%7Baligned%7D = 167.199 \; \mathrm%7BkN%7D

 

Rn

Image Removed

Mathinline
body--uriencoded--\normalsize R_%7Bn%7D = n_e \times R_%7Bn,edge%7D + n_s \times R_%7Bn,spacing%7D

Mathinline
body--uriencoded--$$ \normalsize R_%7Bn%7D = 4 \times 167.199 = 668.797 \; \mathrm%7BkN%7D $$

 

Rn / Ω

Mathinline
body--uriencoded--$$ \normalsize R_n/ \Omega = 668.797 / 2 = 334.399 \; \; \mathrm%7BkN%7D $$

 

Required

Available

Check

Result

31.564 kN

334,399 kN

0.094

Beam Shear Yield

In the case of the block shear limit state, the gross area yielding of the tensile plane The shear strength of connecting elements in shear is the minimum value obtained according to the limit states of shear yielding and shear rupture. Shear yielding is checked according to AISC 360-16.

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Required

Available

Check

Result

31.564 kN

122.166 kN

0.258

Plate Shear Yield

The gross area yielding of the tensile plane shear strength of connecting elements in shear is the minimum value obtained according to the limit states of shear yielding and shear rupture. Shear yielding is checked according to AISC 360-16.

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Required

Available

Check

Result

31.564 kN

338.77 kN

0.093

Plate Shear Rupture

The net area rupture of the tensile plane of the connection part shear strength of connecting elements in shear is the minimum value obtained according to the limit states of shear yielding and shear rupture. Shear rupture is checked according to AISC 360-16.

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Ag

Mathinline
body--uriencoded--\normalsize A_%7Bg%7D = (60 + 45) \times 12 \times 2 = 2520 \; \; \mathrm%7Bmm%5e2%7D

 

Anv

Mathinline
body--uriencoded--\normalsize A_%7Bnv%7D = ((60 + 45)-1.5 \times 20) \times 12 \times 2 = 1800 \; \; \mathrm%7Bmm%5e2%7D

 

Ant

Mathinline
body--uriencoded--\normalsize A_%7Bnt%7D = 2 \times 12 \times (40-0.5 \times 20) = 720 \; \; \mathrm%7Bmm%5e2%7D

 

Fy

235.359 N/mm2

 

Fu

362.846 N/mm2

 

Ubs

1.0

 

 

Mathinline
body--uriencoded--$$ \normalsize U_%7Bbs%7DF_%7Bu%7DA_%7Bnt%7D=1 \times 362.846 \times 10%5e%7B-3%7D \times 720 = 261. 25 $$
Mathinline
body--uriencoded--$$ \normalsize 0.6 F_%7Bu%7D A_%7Bnv%7D = 0.6 \times 362.846 \times 10%5e%7B-3%7D \times 1800 = 391.874 $$
Mathinline
body--uriencoded--$$ \normalsize 0.6 F_%7By%7D A_%7Bg%7D = 0.6 \times 235.359 \times 10%5e%7B-3%7D \times 2520 = 355.863 $$

 

Rn

Mathinline
body--uriencoded--\begin%7Baligned%7D \normalsize R_n = \mathrm%7Bmin%7D \left[\begin%7Bmatrix%7D 0.6F_uA_%7Bnv%7D \\0.6F_yA_%7Bg%7D \end%7Bmatrix%7D\right] \end%7Baligned%7D + U_%7Bbs%7DF_uA_%7Bnt%7D

Mathinline
body--uriencoded--$$ \normalsize R_%7Bn%7D =355.863 + 261.25 = 617.113 \; \mathrm%7BkN%7D $$

AISC 360-16 J4-5

Rn / Ω

Mathinline
body--uriencoded--$$ \normalsize R_n/ \Omega = 617.113 / 2 = 308.556 \; \; \mathrm%7BkN%7D $$

 

Required

Available

Check

Result

31.564 kN

308.556 kN

0.102

Welding Strength

Fe

480000 kN480 N/mmm2

w

7.07 mm

Fu

362.846  N/mm2

t

6.2 mm

l

135.856 mm

Rnw

Mathinline
body--uriencoded--$$ \normalsize R_%7Bnw%7D = 0.6 \times F_e \times 2 \times 0.707 \times w \times l $$
Mathinline
body--uriencoded--$$ \normalsize R_%7Bnw%7D = 0.6 \times 480 \times 2 \times 0.707 \times 7.072 \times 135.856 \times 10%5e%7B-3%7D = 391.258 \; \mathrm%7BkN%7D $$

RnBM

Mathinline
body--uriencoded--$$ \normalsize R_%7BnBM%7D = 0.6 F_u t l = 0.6 \times 362.846 \times 6.2 \times 135.856 \times 10%5e%7B-3%7D = 183.376\; \mathrm%7BkN%7D $$

Rn

Mathinline
body--uriencoded--$$ \normalsize R_n = min (R_%7Bnw%7D,R_%7BnBM%7D) = 183.376\; \mathrm%7BkN%7D $$

Rn / Ω

Mathinline
body--uriencoded--$$ \normalsize R_n/ \Omega = 183.376 / 2 = 91.688 \; \; \mathrm%7BkN%7D $$

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