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  • The shear strength of steel elements is calculated automatically according to AISC 360-16.

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Symbols

Fy = Specified minimum yield stress
E = Modulus of elasticity of steel = 29,000 ksi (200 000 MPa)
λr= Limiting width-to-thickness parameter for noncompact element
λp )
Fy = Specified minimum yield stress
h = clear distance between flanges less the fillet at each flange, in. (mm)
Vn = Nominal shear strength, kips (N)
tw = thickness of web, in. (mm)
λw = Limiting width-to-thickness parameter for compact element

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In design per share, it is assumed that shear force is completely carried by the web, no interaction between bending and shear occurs, yield stress in shear is,

Mathinline
body$$ \normalsize f_y \cong 0.60 F_y $$

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$$

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  • The design shear strength =

    Mathinline
    body$$ \normalsize \phi_vV_n $$

  • The design shear strength =

    Mathinline
    body$$ \normalsize V_n/\Omega_v $$

Mathinline
body$$ \normalsize \phi_v=0.90 \;\; (LRFD) \;\;\;\;\;\;\;\;\;\; \Omega_v=1.67 \;\; (ASD) $$

The nominal shear strength, Vn, shall be determined depending on the slenderness defined by (h/tw) according to the limit state of shear yielding and shear buckling.

  • If

    Mathinline
    body--uriencoded--$$ \normalsize \lambda_w=\dfrac%7Bh%7D%7Bt_w%7D \le \lambda_%7Bpv%7D=2.24 \sqrt%7B \dfrac%7BE%7D%7BF_y%7D %7D $$
    satisfies, shear yielding controls.

  • If

    Mathinline
    body--uriencoded--$$ \normalsize \lambda_w=\dfrac%7Bh%7D%7Bt_w%7D > \lambda_%7Bpv%7D=2.24 \sqrt%7B \dfrac%7BE%7D%7BF_y%7D %7D $$
    satisfies, shear buckling controls.

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