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Tip
  • The shear strength of rectangular HSS, box sections, and other singly and doubly symmetric members is calculated automatically according to AISC 360-16.

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Symbols

Aw = Shear area
Ag = gross cross-sectional area of the member, in.2 (mm2)
b = width of the leg resisting the shear force or depth of the tee stem, in. (mm)
Cv2 = web shear buckling strength coefficient.
E = Modulus of elasticity of steel = 29,000 ksi (200 000 MPa)
Fy = specified minimum yield stress of the type of steel being used, ksi (MPa)
h = clear distance between flanges less the fillet at each flange, in. (mm)
Vn = Nominal shear strength, kips (N)
t = thickness of angle leg or tee stem, in. (mm)
λw = Limiting width-to-thickness parameter

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Mathinline
body--uriencoded--$$ \normalsize V_n = 0.6F_yA_wC_%7Bv2%7D \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; (G4-1) $$

  • Mathinline
    body--uriencoded--$$ \normalsize \mathrm%7BWhen%7D \;\; h/t_w \le 1.10 \sqrt%7Bk_vE/F_y%7D \;\;\;\;\;\;\;\;\;\;\; C_%7Bv2%7D=1.0 \;\;\;\;\;\;\;\;\;\;\;\;\;\; \;\;\;\;\;\;\;\;\;\;\;\;\;\; (G2-9) $$

  • Mathinline
    body--uriencoded--$$ \normalsize \mathrm%7BWhen%7D \;\; 1.10 \sqrt%7Bk_vE/F_y%7D < h/t_w < 1.37 \sqrt%7Bk_vE/F_y%7D \;\;\;\;\;\;\;\;\;\;\; C_%7Bv2%7D= \dfrac%7B1.0\sqrt%7Bk_vE/F_y%7D%7D%7Bh/t_w%7D \;\;\;\;\;\;\;\;\;\;\;\;\;\; \;\;\;\;\; (G2-10) $$

  • Mathinline
    body--uriencoded--$$ \normalsize \mathrm%7BWhen%7D \;\; h/t_w > 1.37 \sqrt%7Bk_vE/F_y%7D \;\;\;\;\;\;\;\;\;\;\; C_%7Bv2%7D= \dfrac%7B1.51k_vE%7D%7B(h/t_w)%5e2F_y%7D \;\;\;\;\;\;\;\;\;\;\;\;\;\; \;\;\;\;\;\;\;\;\;\;\;\;\;\; (G2-11) $$

and

Mathinline
body$$ \normalsize h/t_w = h/t \; \; \; \; \;\;\;\;\; k_v=5 $$

The nominal shear strength, Vn, for round HSS is calculated as shown below.

Mathinline
body--uriencoded--$$ \normalsize V_n =F_%7Bcr%7DA_g/2 \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; \; \; \; \; \;\;\;\;\; (G5-1) $$

Mathinline
body--uriencoded--\begin%7Baligned%7D \normalsize F_%7Bcr%7D = max \begin%7Bbmatrix%7D F_%7Bcr%7D=\dfrac%7B1.6E%7D%7B\sqrt%7B\dfrac%7BL_v%7D%7BD%7D%7D\bigg(\dfrac%7BD%7D%7Bt%7D\bigg)%5e%7B5/4%7D%7D & &,&& F_%7Bcr%7D=\dfrac%7B0.78E%7D%7B\bigg(\dfrac%7BD%7D%7Bt%7D\bigg)%5e%7B3/2%7D%7D \end%7Bbmatrix%7D \end%7Baligned%7D

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