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İnternational Design Codes

ACI 318-19 : Flexural Strength

TSC 2018 : TSC Flexural Strength

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Notation

As = area of nonprestressed longitudinal tension reinforcement, in2
α = depth of equivalent rectangular stress block, in.
bw = web width or diameter of circular section, in.
c = distance from extreme compression fiber to neutral axis, in.
Cc = concretecompressive force, lb
Cs = reinforcement tension force, lb
d = distance from extreme compression fiber to centroid of longitudinal tension reinforcement, in.
fc'= specified compressive strength of concrete, psi
fy = specified yield strength for nonprestressed reinforcement, psi
Mn = nominal flexural strength at section, in.-lb
ϕ = strength reduction factor
εt = net tensile strain in extreme layer of longitudinal tension reinforcement at nominal strength, excluding strains due to effective prestress, creep, shrinkage, and temperature
β1 = factor relating depth of equivalent rectangular compressive stress block to depth of neutral axis

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  • Maximum strain at the extreme concrete compression fiber is assumed equal to 0.003.

  • Tensile strength of concrete is neglected.

  • The relationship between concrete compressive stress and strain is represented by equivalent rectangular concrete stress distribution method.

  • Concrete stress of 0.85fc' is assumed uniformly distributed over. Equivalent rectangular concrete stress zone bounded by edges of the cross section and a line parallel to the neutral axis located a distance α from the fiber of maximum compressive strain, as calculated by:

Mathinline
body$$ α --uriencoded--$$ \normalsize %7Bα = β_1c $$

Unit
body$$ α = β_1c $$

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anchorasda
alignmentcenter
$$ α = β_1c $$ 

1c%7D $$

  • The distance between the fiber of maximum compressive stress and the neutral axis, c, is perpendicular to the neutral axis.

  • The value of β1 is determined using Codes.

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The total forces Cc and Cs resulting from the stresses of concrete and reinforcement are shown below.

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Mathinline
body--uriencoded--$$ \normalsize C_c = 0.85f_c%5e'(b_wα) $$
Mathinline
body$$ \normalsize C_s = A_sf_y $$

From the equation of equilibrium:

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Mathinline
body$$ \normalsize C_c = C_s $$
Mathinline
body--uriencoded--$$ \normalsize A_sf_y = 0.85f_c%5e'(b_wα) $$

Nominal flexural strength Mn:

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Mathinline
body--uriencoded--$$ \normalsize M_n = 0.85f_c%5e'(b_wα)(d-\frac α 2) $$
or
Mathinline
body$$ \normalsize M_n = A_sf_y(d-\frac α 2) $$

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