Column Formwork Scaffolding Design Example

Wooden scaffolding calculation will be made for the 30x60 column of the project, which includes the plan and 3D model image.

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• Plywood thickness t=18 mm,

• Plywood Flexural strength f_el = 30 MPa

• Plywood Shear strength f_ek = 3.0 MPa

• Plywood Modulus of Elasticity E_l = 10000 MPa

• Concrete placing speed in the formwork R = 2m/hour

• Concrete casting temperature T = 20°C

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Ƥ_max = p = 58.5 kN/m² = 0.0585 N/mm²

Primary beam interval, L_bk

• b_l = 1000 mm t_l = 18 mm

• A_l = t_l * b_l = 18x1000 = 18000 mm²

• I_l = [ b_l * ( t_l ^3) ]/ 12 = 486000 mm⁴

• S_l = I_l / ( t_l / 2)= 54000 mm³

• Ƥ_max = p = 58.5 kN/m² = 0.0585 N/mm²

Secondary beam interval, L_ik

H20 was chosen as the primary beam section.

• A_bk = 9640 mm²

• I_bk = 45701333.333 mm⁴

• S_bk = 457013.333 mm³

Primary Beam material properties

• f_ebk = 30 MPa

• f_ebk = 3.0 MPa

• E_bk = 14000 MPa

• Lbk = 364.3mm

• A_bk = 9640 mm²

• I_bk = 45701333.333 mm⁴

• S_bk = 457013.333 mm³

• f_ebk = 30 MPa

• f_ebk = 3.0 MPa

• E_bk = 14000 MPa

Rod Interval, L_b

2xUPN 80 was chosen as the secondary beam section.

• A_ik = 2185.3 mm²

• L_ik = 2.0921x10 6 mm⁴

• S_ik = 52303 mm³

Secondary Beam material properties

• f_eik = 235 MPa

• f_eq = 141 MPa

• E_ik = 200000 MPa

• Rod diameter Φ = 17 mm

• L_ik = 753.8 mm

• A_ik = 2185.3 mm²

• I_ik= 2.0921x10 6 mm⁴

• S_ik = 52303 mm³

• f_eik = 30 MPa

• f_eik = 3.0 MPa

• E_ik = 14000 MPa

• Rod diameter Φ = 17 mm

• Rod tensile capacity, N_d,b

• N_d,b = [ ( π* ² ) / 4 f_yb = [ ( π*172 ) / 4 ] 235 = 53340.32 N = 53.34 kN

Prop Control

• Axial load capacity of the support N_d = 9.7 kN

• c = 1.2

• q = 0.5 kN/m 2

In a 30/60 column, the worst case will occur on the 60 cm side.

• w = q x c x b = 1.2 x 0.5 x 0.6 = 0.36 kN/m

• W = w x h = 0.36 x 3 =1.08 kN

• N_pc = 1,278 kN < N_d = 9.7 kN

Example of scaffolding drawings